Take the intersection of an arbitrary number of lists in python

Question

Suppose I have a list of lists of elements which are all the same (i\'ll use ints in this example)

[range(100)[::4], range(100)[::3], range(100)         


        

Answer 1

l = [range(100)[::4], range(100)[::3], range(100)[::2], range(100)[::1]]
l = [set(i) for i in l]
intersect = l[0].intersection(l[1])
for i in l[2:]:
    intersect = intersect.intersection(i)