Take the intersection of an arbitrary number of lists in python

Question

Suppose I have a list of lists of elements which are all the same (i\'ll use ints in this example)

[range(100)[::4], range(100)[::3], range(100)         


        

Answer 1

I'm going to answer my own question:

lists =  [range(100)[::4],range(100)[::3],range(100)[::2],range(100)[::1]]

out = set(lists[0])
for l in lists[1:]:
    out = set(l).intersection(out)

print out

or

print list(out)