std::cout deal with uint8_t as a character

Question

If I run this code:

std::cout << static_cast(65);

It will output:

A

Which

Answer 1

Posting an answer as there is some misinformation in comments.

The uint8_t may or may not be a typedef for char or unsigned char. It is also possible for it to be an extended integer type (and so, not a character type).

Compilers may offer other integer types besides the minimum set required by the standard (short, int, long, etc). For example some compilers offer a 128-bit integer type.

This would not "conflict with C" either, since C and C++ both allow for extended integer types.

So, your code has to allow for both possibilities. The suggestion in comments of using unary + would work.

Personally I think it would make more sense if the standard required uint8_t to not be a character type, as the behaviour you have noticed is unintuitive.