Why I can't directly set console.log() as callback function

Question

Why this code doesn\'t work

function callback(num, func) {
    for(var i = 0; i < num; i++) {
        func();
    }
}

callback(4, console.log(\"Hello         


        

Answer 1

That's because when you mentioned console.log(), you asked the js engine to evaluate it and it does and passes the result as the 2nd arg to the callback function and not a function object as it expects and hence the call doesn't behave as u desire. The working case correctly passes a function object when u pass a function(){} construct.