How to allocate an array inside fortran routine “called” from C

Question

I think title says what I need. I know we can use \"asd\" function to do this, but for some reasons I need to do the allocation in Fortran (i.e. in subroutine \"asd_\"). Her

Answer 1

Here is also another solution, if you want to use Fortran intrinsic types. This was my case, since I needed to call routines from an external library, using the pre-specified data types. This is basically done with a wrapper Fortran subroutine. Here is the C code:

void mywrap_(void **);
void myprint_(void *);

main () {
  void *d;
  mywrap_(&d);
  myprint_(d);
  return 0;
}

And here is the wrapper:

  subroutine mywrap(b)
  implicit none
  include "h.h"     
  type(st), target, save :: a
  integer, pointer :: b
  interface 
     subroutine alloc(a)
        include "h.h"
        type(st) a
     end subroutine alloc
  end interface

  call alloc(a)
  b => a%i
  end

And the Fortran codes:

  subroutine alloc(a)
  implicit none 
  include "h.h"
  type(st) a

  a%i = 2
  a%r = 1.5
  if (allocated(a%s)) deallocate(a%s)
  allocate(a%s(2))
  a%s(1) = 1.23
  a%s(2) = 1234
  end
  !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
  subroutine myprint(a)
  implicit none
  include "h.h"     
  type(st) a

  print *,"INT: ", a%i
  print *,"REAL: ", a%r
  print *,"ALLOC: ", a%s
  end

And the header file "h.h":

  type st
     sequence
     integer i
     real r
     real, allocatable :: s(:)
  end type

Note, this way all the objects are opaque in the C.