Command line arguments in C

Question

I have this program execute with the values 10,20,30 given at command line.

int main(int argc , char **argv)
 { 
  printf(\"\\n Printing the arguments of a         


        

Answer 1

Because you're printing out argv[4], argv[3], argv[2], argv[1], argv[0], instead of argv[3], argv[2], argv[1], argv[0].

Basically you've got an off by one error.