string s1 = \"test\";
string s5 = s1.Substring(0, 3)+\"t\";
string s6 = s1.Substring(0,4)+\"\";
Console.WriteLine(\"{0} \", object.ReferenceEquals(s1, s5)); //Fa
From msdn documentation of object.ReferenceEquals here:
When comparing strings.If objA and objB are strings, the ReferenceEquals method returns true if the string is interned.It does not perform a test for value equality.In the following example, s1 and s2 are equal because they are two instances of a single interned string.However, s3 and s4 are not equal, because although they are have identical string values, that string is not interned.
using System;
public class Example
{
public static void Main()
{
String s1 = "String1";
String s2 = "String1";
Console.WriteLine("s1 = s2: {0}", Object.ReferenceEquals(s1, s2));
Console.WriteLine("{0} interned: {1}", s1,
String.IsNullOrEmpty(String.IsInterned(s1)) ? "No" : "Yes");
String suffix = "A";
String s3 = "String" + suffix;
String s4 = "String" + suffix;
Console.WriteLine("s3 = s4: {0}", Object.ReferenceEquals(s3, s4));
Console.WriteLine("{0} interned: {1}", s3,
String.IsNullOrEmpty(String.IsInterned(s3)) ? "No" : "Yes");
}
}
// The example displays the following output:
// s1 = s2: True
// String1 interned: Yes
// s3 = s4: False
// StringA interned: No