Boolean Python Value confusion

Question

I\'m new to Python and while trying Python logical statements.I came across this which I\'m not able to understand.Can anyone tell me whats happening here in Python 2.7.What

Answer 1

You are being confused by the behaviour of the or operator; it returns the first expression that only if it is a true value; neither 0 nor False is true so the second value is returned:

>>> 0 or 'bar'
'bar'
>>> False or 'foo'
'foo'

Any value that is not numerical 0, an empty container, None or False is considered true (custom classes can alter that by implementing a __bool__ method (python 3), __nonzero__ (python 2) or __len__ (length 0 is empty).

The second expression is not even evaluated if the first is True:

>>> True or 1 / 0
True

The 1 / 0 expression would raise a ZeroDivision exception, but is not even evaluated by Python.

This is documented in the boolean operators documentation:

The expression x or y first evaluates x; if x is true, its value is returned; otherwise, y is evaluated and the resulting value is returned.

Similarly, and returns the first expression if it is False, otherwise the second expression is returned.