How do I use grep to extract a specific field value from lines

Question

I have lines in a file which look like the following

....... DisplayName=\"john\" ..........

where .... represents variable nu

Answer 1

This works for me:

awk -F "=" '/DisplayName/ {print $2}'

which returns "john". To remove the quotes for john use:

awk -F "=" '/DisplayName/ {gsub("\"","");print $2}'