Processing a file character by character in Clojure

Question

I\'m working on writing a function in Clojure that will process a file character by character. I know that Java\'s BufferedReader class has the read() method that reads one

Answer 1

(with-open [reader (clojure.java.io/reader "path/to/file")] ...

I prefer this way to get a reader in clojure. And, by character by character, do you mean in file access level, like read, which allow you control how many bytes to read?

Edit

As @deterb pointed out, let's check the source code of line-seq

(defn line-seq
  "Returns the lines of text from rdr as a lazy sequence of strings.
   rdr must implement java.io.BufferedReader."
  {:added "1.0"
   :static true}
  [^java.io.BufferedReader rdr]
  (when-let [line (.readLine rdr)]
    (cons line (lazy-seq (line-seq rdr)))))

I faked a char-seq

 (defn char-seq 
   [^java.io.Reader rdr]
   (let [chr (.read rdr)]
     (if (>= chr 0)
     (cons chr (lazy-seq (char-seq rdr))))))

I know this char-seq reads all chars into memory[1], but I think it shows that you can directly call .read on BufferedReader. So, you can write your code like this:

(let [chr (.read rdr)]
  (if (>= chr 0)
    ;do your work here
  ))

How do you think?

[1] According to @dimagog's comment, char-seq not read all char into memory thanks to lazy-seq