incrementing an array of pointers in C

Question

this is probably an essentially trivial thing, but it somewhat escapes me, thus far..

char * a3[2];
a3[0] = \"abc\";
a3[1] = \"def\";
char ** p;


Answer 1

Try

char *a3Ptr = a3;
printf("%p - \"%s\"\n", a3, *(++a3Ptr));

In C, a char array[] is different from char*, even if you can use a char* to reference the first location of an array of char.

aren't both "p" and "a3" pointers to pointers?

Yes but a3 is constant. You can't modify it.