Ambiguous call to overloaded function 'pow'

Question

I\'m having some problems runnning the following code. I got this: error C2668: \'pow\' : ambiguous call to overloaded function. I\'ve tried to manually cast the arguments t

Answer 1

In C language we can find library function under math.h:

double pow(double x, double y) ---- 1**

In C++ language we able to have set of overloaded functions under cmath such as:

float       pow( float base, float exp ) ---- 2
double      pow( double base, double exp ) ---- 3
long double pow( long double base, long double exp ) ---- 4
float       pow( float base, int iexp ) ---- 5
double      pow( double base, int iexp ) ---- 6
long double pow( long double base, int iexp ) ---- 7

Since you were using C style programming but compiled using C++ compiler,compiler might face with ambiguity states with defined function in math library,therefore you should convert your argument appropriately according to function definition 1 as mentioned above,therefore change your code as,

result += (n[i] - 'a' + 10)* pow(16.0, static_cast(strlen(n) - i - 1))

ALSO NOTED with in your given code snippet there is a mistake as Perreal noted

if (n[i] >= 'A')
            result += (n[i] - "A" + 10)* pow(16, strlen(n) - i - 1);

you cannot do arithmetic operations with string literals.change it as Ptefan mentioned ,also change int result to double result if you need high precision and accurate results.