Call by reference, value, and name

Question

I\'m trying to understand the conceptual difference between call by reference, value, and name.

So I have the following pseudocode:

foo(a, b, c)
{
           


        

Answer 1

This won't change the value of X, Y or Z if it is pass-by-value. When you use a function such as "foo()", it basically copies the variables (x, y and z) into other variables (a, b, and c) and does certain actions with them, without changing the originals (x, y and z). For you to change a value you would have to return a value, something like this:

foo(a, b, c)
{
a = a++;
b = b++;
c = a + b * 10;
return c;
}

x = 1;
y = 2;
z = 3;
z = foo(x, y+2)

Then x and y would be the same, but z would be (x+1)+(y+1)*10 which in this case would be 32.