C++ popen command without console

Question

when I use popen to get the output of a command, say dir, it will prompt out a console.

however, can I get the output of a command without the appearance of the cons

Answer 1

With POSIX it should be something like this:

//Create the pipe.
int lsOutPipe[2];
pipe(lsOutPipe);

//Fork to two processes.
pid_t lsPid=fork();

//Check if I'm the child or parent.
if ( 0 == lsPid )
{//I'm the child.
  //Close the read end of the pipe.
  close(lsOutPipe[0]);

  //Make the pipe be my stdout.
  dup2(lsOutPipe[1],STDOUT_FILENO);

  //Replace my self with ls (using one of the exec() functions):
  exec("ls"....);//This never returns.  
} // if

//I'm the parent.
//Close the read side of the pipe.
close(lsOutPipe[1]);

//Read stuff from ls:
char buffer[1024];
int bytesRead;
do
{
  bytesRead = read(emacsInPipe[0], buffer, 1024);

  // Do something with the read information.
  if (bytesRead > 0) printf(buffer, bytesRead);
} while (bytesRead > 0);

You should off course check return values etc...