Does x86-SSE-instructions have an automatic release-acquire order?

Question

As we know from from C11-memory_order: http://en.cppreference.com/w/c/atomic/memory_order

And the same from C++11-std::memory_order: http://en.cppreference.com/w/cpp

Answer 1

Here is an excerpt from Intel's Software Developers Manual, volume 3, section 8.2.2 (the edition 325384-052US of September 2014):

• Reads are not reordered with other reads.
• Writes are not reordered with older reads.
• Writes to memory are not reordered with other writes, with the following exceptions:
  • writes executed with the CLFLUSH instruction;
  • streaming stores (writes) executed with the non-temporal move instructions (MOVNTI, MOVNTQ, MOVNTDQ, MOVNTPS, and MOVNTPD); and
  • string operations (see Section 8.2.4.1).
• Reads may be reordered with older writes to different locations but not with older writes to the same location.
• Reads or writes cannot be reordered with I/O instructions, locked instructions, or serializing instructions.
• Reads cannot pass earlier LFENCE and MFENCE instructions.
• Writes cannot pass earlier LFENCE, SFENCE, and MFENCE instructions.
• LFENCE instructions cannot pass earlier reads.
• SFENCE instructions cannot pass earlier writes.
• MFENCE instructions cannot pass earlier reads or writes.

The first three bullets describe the release-acquire ordering, and the exceptions are explicitly listed there. As you might see, only cacheability control instructions (MOVNT*) are in the exception list, while the rest of SSE/SSE2 and other vector instructions obey to the general memory ordering rules, and do not require use of [LSM]FENCE.