jQuery each always sort it?

Question

I have this object in JS:

var list = {134 : \"A\",140 : \"B\",131 : \"C\"}

I run it with:

jQuery.each(list, function(key, v         


        

Answer 1

First off: that's not a list, it's an object. Object's order is not guaranteed to be kept - each implementation may choose a different ordering.

On the other hand, arrays do preserve order:

var list = [[134, "A"],[140, "B"],[131, "C"]];


jQuery.each(list, function(i, obj) { 
  console.log(i + " - " + obj[0] + " - " + obj[1]);
});