Is there a way to completely delete fields in awk, so that extra delimiters do not print?

Question

Consider the following command:

$ gawk -F"\\t" "BEGIN{OFS=\\"\\t\\"}{$2=$3=\\"\\"; p         


        

Answer 1

In the addition of the answer by Suicidal Steve I'd like to suggest one more solution but using sed instead awk.

It seems more complicated than usage of cut as it was suggested by Steve. But it was the better solution because sed -i allows editing in-place.

$ sed -i 's/\(.*,\).*,.*,\(.*\)/\1\2/' FILENAME