Can you declare a object literal type that allows unknown properties in typescript?

Question

Essentially I want to ensure that an object argument contains all of the required properties, but can contain any other properties it wants. For example:

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Answer 1

Well, i hate answering my own questions, but the other answers inspired a little thought... This works:

function foo(bar: T): void {
    console.log(bar.baz);
}

foo({baz: 1, other: 2});