HTML5 Input type “number” in Firefox

Question

I am working on an app that is only used by a few people in-house, so I feel comfortable telling them to only use Firefox or Chrome, so I can use HTML5.

I was workin

Answer 1

i am using firefox, i had the same issue developing my input type number typing caracters and spaces etc... anyway i m using angular 2 in this examples, its almost similar to javascript, so you can use this code in every case : here is the html :

here is the function FilterInput :

FilterInput(event: any) {
        let numberEntered = false;
        if ((event.which >= 48 && event.which <= 57) || (event.which >= 37 && event.which <= 40)) { //input number entered or one of the 4 directtion up, down, left and right
            //console.log('input number entered :' + event.which + ' ' + event.keyCode + ' ' + event.charCode);
            numberEntered = true;
        }
        else {
            //input command entered of delete, backspace or one of the 4 directtion up, down, left and right
            if ((event.keyCode >= 37 && event.keyCode <= 40) || event.keyCode == 46 || event.which == 8) {
                //console.log('input command entered :' + event.which + ' ' + event.keyCode + ' ' + event.charCode);
            }
            else {
                //console.log('input not number entered :' + event.which + ' ' + event.keyCode + ' ' + event.charCode);
                event.preventDefault();
            }
        }
        // input is not impty
        if (this.validForm) {
            // a number was typed
            if (numberEntered) {
                let newNumber = parseInt(this.numberVoucher + '' + String.fromCharCode(event.which));
                console.log('new number : ' + newNumber);
                // checking the condition of max value
                if ((newNumber <= 30 && newNumber >= 1) || Number.isNaN(newNumber)) {
                    console.log('valid number : ' + newNumber);
                }
                else {
                    console.log('max value will not be valid');
                    event.preventDefault();
                }
            }
            // command of delete or backspace was types
            if (event.keyCode == 46 || event.which == 8) {
                if (this.numberVoucher >= 1 && this.numberVoucher <= 9) {
                    console.log('min value will not be valid');
                    this.numberVoucher = 1;
                    //event.preventDefault();
                    this.validForm = true;
                }
            }
        }
        // input is empty
        else {
            console.log('this.validForm = true');
            this.validForm = false;
        }
    };

in this function i had to just let the keypress of numbers, direction, deletes enter, so this function is just for the positive integer not doubles.