How does in assembly does assigning negative number to an unsigned int work?

Question

I Learned About 2\'s Complement and unsigned and signed int. So I Decided to test my knowledge , as far as i know that a negative number is stored in 2\'s

Answer 1

There are a few differences between signed and unsigned types:

1. The behaviors of the operators <, <=, >, >=, /, %, and >> are all different when dealing with signed and unsigned numbers.

2. Compilers are not required to behave predictably if any computation on a signed value exceeds the range of its type. Even when using operators which would behave identically with signed and unsigned values in all defined cases, some compilers will behave in "interesting" fashion. For example, a compiler given x+1 > y could replace it with x>=y if x is signed, but not if x is unsigned.

As a more interesting example, on a system where "short" is 16 bits and "int" is 32 bits, a compiler given the function:

unsigned mul(unsigned short x, unsigned short y) { return x*y; }

might assume that no situation could ever arise where the product would exceed 2147483647. For example, if it saw the function invoked as unsigned x = mul(y,65535); and y was an unsigned short, it may omit code elsewhere that would only be relevant if y were greater than 37268.