problem with printf function?

Question

i wrote the following program

 #include 

 main()
 {
 int i = 2;
 float c = 4.5;
 printf(\"%d\\n\",c);
 printf(\"%f\\n\",i);
 return 0;
 }
         


        

Answer 1

printf doesn't convert it's arguments. It's looking at the memory containing a float and printing it as if it were an integer - it's like taking an MP3 file and asking word to open it as if it were a doc.

A floating point number is stored in a completely different way in memory to an integer - it's not just an integer with some decimal points