Why is the assignment operator not called in this case in favor of the copy constructor?

Question

From the wikipedia page for copy constructors:

X a = X();     

// valid given X(const X& copy_from_me) but not valid given X(X& copy_from_me)
// bec         


        

Answer 1

It's simply a matter of understanding the grammar of C++. The statement X a = X(); is a declaration statement with initializer, and not an assignment expression. The grammatical meaning of this statement is to declare a variable a of type X and copy-initialize it from the expression X(). There is no assign­ment involved here in any way.