How do i print escape characters as characters?

Question

I\'m trying to print escape characters as characters or strings using this code:

while((c = fgetc(fp))!= EOF)
{
    if(c == \'\\0\')
    {
        printf(\"          


        

Answer 1

Backslashes in string literals need to be escaped; instead of "\0", you need "\\0".

A lookup table might make this less painful:

const char *ecs[256] = {NULL}; // assumes ASCII - may not be a valid assumption
int c;

ecs['\0'] = "\\0";
ecs['\a'] = "\\a";
ecs['\b'] = "\\b";
...
while ((c = fgetc(fp)) != EOF)
{
  if (ecs[c] == NULL)
    printf("%c", c);
  else
    printf("%s", ecs[c]);
}

Yes, the majority of entries in ecs are going to be NULL; the tradeoff is that I don't have to worry about mapping the character value to array index.