unexpectedly found nil while unwrapping an Optional value keyboardWillShow

Question

I have this code below which runs when the keyboardWillShowNotification is called:

func keyboardWillShow(_ notification: Notification) {
    //ERROR IN THE L         


        

Answer 1

(How to fix your issue is clearly written in Leo Dabus's answer, so I will try to explain the error I was getting before I added the ! .)

In Swift 3, as AnyObject has become one of the most risky operation. It's related to the worst new feature called as id-as-Any.

In this line of your code:

    keyboard = (notification.userInfo?[UIKeyboardFrameEndUserInfoKey] as AnyObject).cgRectValue

The type of expression notification.userInfo?[UIKeyboardFrameEndUserInfoKey] is Any?. As you see, an Optional type Any? should not be safely converted to non-Optional AnyObject. But Swift 3 converts it with creating non-Optional _SwiftValue.

You can check this behaviour with inserting this code:

print(type(of: notification.userInfo?[UIKeyboardFrameEndUserInfoKey] as AnyObject))

So, you are trying to apply non-optional-chaining .cgRectValue to _SwiftValue, which may be confusing the Swift 3's feature: "implicit type conversion _SwiftValue back to the Swift value".

Getting too long...

---

Do NOT use as AnyObject casting in Swift 3