Typecasting int to char in printf() in C

Question

int *int_pointer = malloc(10);

*int_pointer = 53200;

printf(\"The integer at byte #0 is set to: %d \\n\", (char) *int_pointer);

RESULT: -48

Answer 1

That's simple: 53200 = 0xCFD0 and 0xCF = 207 which for a signed char = -48 ...