How to pass constructor's parameters with jackson?

Question

i am trying to desearlize an object using Jackson

this.prepareCustomMapper().readValue(response.getBody(), EmailResponse.class);

and i have

Answer 1

You can write your custom deserializer: http://jackson.codehaus.org/1.5.7/javadoc/org/codehaus/jackson/map/annotate/JsonDeserialize.html

In that case you will be able to pass any values that you want into the constructor. You will need to add @JsonDeserialize annotation on EmailResponse like:

@JsonDeserialize(using = EmailResponseDeserializer.class)

Deserializer implementation example:

public class EmailResponseDeserializer extends JsonDeserializer {
    HttpResponse httpResponse;

    public EmailResponceDeserializer(HttpResponse httpResponse) {
        this.httpResponse = httpResponse;
    }

    @Override
    public EmailResponse deserialize(JsonParser jp, DeserializationContext ctxt) 
      throws IOException, JsonProcessingException {
        JsonNode node = jp.getCodec().readTree(jp);
        int id = (Integer) ((IntNode) node.get("id")).numberValue();
        String email = node.get("email").asText();

        EmailResponse emailResponse = new EmailResponse(httpResponse)
        emailResponse.setId(id);
        emailResponse.setEmail(email);
        // other properties

        return emailResponse;
    }
}

Also you will need to register the custom deserializer:

ObjectMapper mapper = new ObjectMapper();
SimpleModule module = new SimpleModule();
module.addDeserializer(EmailResponse.class, new EmailResponseDeserializer(httpRespose));
mapper.registerModule(module);

Generally, I would say that by adding HttpResponse into EmailRespose bean you are adding some implementation into the DTO object which shouldn't have any. I don't think that this is a good idea to set httpResponse into the custom deserialiser and then set it into the EmailResponse but nothing prevent you of doing it.

Hope this helps.