Serialize/Deserialize dynamic property name using JSON.NET

Question

I have the following class:

public class MyRequest
{
    public string Type {get;set;}
    public string Source {get;set;}
}

I would like t

Answer 1

My solution is: First create APIResultModel class:

public class APIResultModel where T: APIModel, new()
{

    public string ImmutableProperty { get; set; }

    public T Result { get; set; }

    public APIResultModel Deserialize(string json)
    {
        var jObj = JObject.Parse(json);
        T t = new T();
        var result = jObj[t.TypeName()];
        jObj.Remove(t.TypeName());
        jObj["Result"] = result;
        return jObj.ToObject>();
    }
}

Second create APIModel abstract Class:

public abstract class APIModel
{
    public abstract string TypeName();
}

Third create dynamic content Model class:

public class MyContentModel: APIModel
{
    public string Property {get; set;}
    public override string TypeName()
    {
        return "JsonKey";
    }
}

When you need to deserialize a json string:

var jsonModel = new APIResultModel();
jsonModel = jsonModel.Deserialize(json);
MyContentModel dynimacModel = jsonModel.Result;

The Deserialize function is come from @Eser