Printing Simple Diamond Pattern in Python

Question

I would like to print the following pattern in Python 3.5 (I\'m new to coding):

    *
   ***
  *****
 *******
*********
 *******
  *****
   ***
    *
         


        

Answer 1

#coder_rishabh_darmwal
#it_is_a_simple_codewith_an_easy_logic
row=int(input('enter the no. of rows')
for i in range(row):
    if i<=row//2:
        for j in range(row//2-i):
            print(" ",end='')
        for k in range(i*2-1):
        print("*",end="")
    print()
else:
    for j in range(i-row//2):
        print(" ",end="")
    for k in range((row-i)*2-1):
        print("*",end="")
    print()
#the output will be
[output for row=30][1]


#i also wrote a programme fro hollow diamonds
row=int(input('enter the no. of rows')
for i in range(row):
    if i<=row//2:
        for j in range(row//2-i):
            print(" ",end='')
        for k in range(i*2-1):
            if k==0 or k==i*2-2:
                print("*",end="")
            else:
                print(' ',end='')
        print()
    else:
        for j in range(i-row//2):
            print(" ",end="")
        for k in range((row-i)*2-1):
            if k==0 or k==(row-i)*2-2:
                print("*",end="")
            else:
                print(' ',end="")
        print()
[out for hollow rhombus row=20
][2]


  [1]: https://i.stack.imgur.com/3j0bx.png
  [2]: https://i.stack.imgur.com/tCxI3.png