Printing Simple Diamond Pattern in Python

Question

I would like to print the following pattern in Python 3.5 (I\'m new to coding):

    *
   ***
  *****
 *******
*********
 *******
  *****
   ***
    *
         


        

Answer 1

simple way ...

n= 11 #input is even number 1,3,5,...
a = 1
b = 1
for a in range(n+1):
    if a%2 != 0:
        val = (n - a) // 2
        print (" "*val + "*"*(a) + " "*val ,end = "\n")
for b in range(n-1,0,-1):
    if b%2 != 0:
        val2 = (n-b)//2
        print (" "*val2 + "*"*(b) + " "*val2 ,end = "\n")

Output:

     *     
    ***    
   *****   
  *******  
 ********* 
***********
 ********* 
  *******  
   *****   
    ***    
     *  

Or using reverse method, first one is diamond, second one is series of diamond

import copy
n = 10       #input: size of diamon
raw  = []
lst = []
re_lst = []

for a in range(n+1):
    if a%2 != 0:
        val = (n - a) // 2
        raw = ''.join(" "*val + "*"*(a) + " "*val)
        lst.append(raw)
        re_lst = copy.deepcopy(lst)
lst.reverse()
#print diamond
for i in re_lst:
    print(i)
for i in lst:
    print(i)
print("\n")
#print series of diamond
for i in re_lst:
    print(i)
    for i in lst:
        print(i)