vbscript - Replace all spaces

Question

I have 6400+ records which I am looping through. For each of these: I check that the address is valid by testing it against something similar to what the Post Office uses (f

Answer 1

This is the syntax Replace(expression, find, replacewith[, start[, count[, compare]]])

it will default to -1 for count and 1 for start. May be some dll is corrupt changing the defaults of Replace function.