Chaining promises without using 'then'

Question

I have an object (foo) that exposes several methods as promises (using jQuery deferred). The way I did it ended up with this kind of code:

var f         


        

Answer 1

Yes sure, you just need to extend your Deferreds to have these methods:

function MyRpc { // if you can use ES2015 - this should be a `class`
  this._deferred = new $.Deferred();
}
// teach it to be a promise
MyRpc.prototype.then = function(onFulfilled, onRejected) {
  return this._deferred.then(onFulfilled, onRejected);
};

// teach it to be a deferred
MyRpc.protototype.resolve = function(arg) {
  this._deferred.resolve(arg);
};

MyRpc.prototype.reject = function(arg) {
  this._deferred.reject(arg);
};

// define your methods!

MyRpc.prototype.method1 = function(arg) {
  var p = this._deferred.then(function(value) {
    // logic of `method1` from foo.method1 here
  });
  var rpc = new MyRpc(); // our continuation;
  p.then(function(v) { rpc.resolve(v) }, function(e) { rpc.reject(e); });
  return rpc;
};

Of course, with a real promise library all this is a lot easier than with jQuery's minimal promises.

This would let you do:

var rpc = new MyRpc();
rpc.method1(1).method1(2).method1(3); // can also `.then` here

I'm not sure it's worth it, but it works.