echo printing -e in bash

Question

I\'ve gotten this script I\'ve created in Bash, and one of the functions I\'m using is echo and I\'m using the -e flag for interpretations of

Answer 1

Remove the trailing backslashes and add a closing quote:

NC='\033[31;0m'       # no colors or formatting
RED='\033[0;31;1m'    # print text in bold red
PUR='\033[0;35;1m'    # print text in bold purple
YEL='\033[0;33;1m'    # print text in bold Yellow
GRA='\033[0;37;1m'    # print text in bold Gray
echo -e "This ${YEL}Message${NC} has color\nwith ${RED}new${NC} lines."

And it works as expected in bash.

If you save this script into a file, run it like bash .

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Try type -a echo to see what it is. The first line of output should be echo is a shell builtin:

$ type -a echo
echo is a shell builtin
echo is /usr/bin/echo
echo is /bin/echo