strip leading zeros in awk program

Question

So I\'m pretty lost as I missed a week and am playing catch up, but I\'m to write an awk program to tell the difference, in days, between two dates.

I\'m more or les

Answer 1

I'm sorry. My answer is not about awk, and it is about bash itself. So please don't give a minus for my comment)

echo -e "00000000" | sed -r 's/^[0]*$/0/g' | sed -r 's/^0[0]+//g'

Or perform integer calculations with (( )) notations

echo $((0000))