SQL - WHERE Condition on SUM()

Question

Is it possible to do something like this:

SELECT 
  `e`.*, 
  `rt`.`review_id`, 
  (SUM(vt.percent) / COUNT(vt.percent)) AS rating 
FROM `catalog_product_ent         


        

Answer 1

This can be accomplished with a HAVING clause:

SELECT e.*, rt.review_id, (SUM(vt.percent) / COUNT(vt.percent)) AS rating 
FROM catalog_product_entity AS e 
INNER JOIN rating_option_vote AS vt ON e.review_id = vt.review_id 
GROUP BY vt.review_id
HAVING (SUM(vt.percent) / COUNT(vt.percent)) >= 0
ORDER BY (SUM(vt.percent) / COUNT(vt.percent)) ASC

Note: Added where to put ORDER BY statement

The query optimizer should also not calculate the Average multiple times either, so that should not be a concern here.

As was mentioned in @jagra's answer, you should be able to use AVG() instead of SUM() / COUNT()