Casting int pointer to char pointer causes loss of data in C?

Question

I have the following piece of code:

#include 
#include 
int main(int argc, char *argv[])
{
  int n = 260; 
  int *p = &n;
         


        

Answer 1

Considering 32 bit systems, 256 will be represented in like this.

00000000 (Byte-3)   00000000 (Byte-2)    00000001(Byte-1)     00000100(Byte-0)

Now when p is typecast-ed to a char pointer, the label on the pointer changes, but the memory contents don't. It means earlier p could have access 4 bytes, as it was an integer pointer, but now it can only access 1 byte as it is a char pointer. So, only the LSB gets changes to zero, not all the 4 bytes.

And it becomes

00000000 (Byte-3)   00000000 (Byte-2)    00000001(Byte-1)     00000000(Byte-0)

Hence, the o/p is 256.