Why shared_ptr has an explicit constructor

Question

I was wondering why shared_ptr doesn\'t have an implicit constructor. The fact it doesn\'t is alluded to here: Getting a boost::shared_ptr for this

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Answer 1

The logical reason is that:

• calling the delete operator is not implicit in C++
• the creation of any owning smart pointer (shared_whatever, scoped_whatever, ...) is really a (delayed) call to the delete operator