Wait for user input in C?

Question

I\'m trying to make a simple command that pauses for user input. I think it\'ll be useful in Bash scripts.

Here\'s my code:

#include 
         


        

Answer 1

From the GNU C Library Manual:

Function: char * fgets (char *s, int count, FILE *stream)

The fgets function reads characters from the stream stream up to and including a newline character and stores them in the string s, adding a null character to mark the end of the string. You must supply count characters worth of space in s, but the number of characters read is at most count − 1. The extra character space is used to hold the null character at the end of the string.

So, fgets(key,1,stdin); reads 0 characters and returns. (read: immediately)

Use getchar or getline instead.

Edit: fgets also doesn't return once count characters are available on the stream, it keeps waiting for a newline and then reads count characters, so "any key" might not be the correct wording in this case then.

You can use this example to avoid line-buffering:

#include 
#include 
#include 

int mygetch ( void ) 
{
  int ch;
  struct termios oldt, newt;
  
  tcgetattr ( STDIN_FILENO, &oldt );
  newt = oldt;
  newt.c_lflag &= ~( ICANON | ECHO );
  tcsetattr ( STDIN_FILENO, TCSANOW, &newt );
  ch = getchar();
  tcsetattr ( STDIN_FILENO, TCSANOW, &oldt );
  
  return ch;
}

int main()
{
    printf("Press any key to continue.\n");
    mygetch();
    printf("Bye.\n");
}