Plotly: How to make a figure with multiple lines and shaded area for standard deviations?

Question

How can I use Plotly to produce a line plot with a shaded standard deviation? I am trying to achieve something similar to seaborn.tsplot. Any help is appreciated.

Answer 1

I was able to come up with something similar. I will post the code here to be used by someone else or for any suggestions for improvements.

import matplotlib,random import plotly.graph_objects as go import numpy as np

#random color generation in plotly
hex_colors_dic = {}
rgb_colors_dic = {}
hex_colors_only = []
for name, hex in matplotlib.colors.cnames.items():
    hex_colors_only.append(hex)
    hex_colors_dic[name] = hex
    rgb_colors_dic[name] = matplotlib.colors.to_rgb(hex)

data = [[1, 3, 5, 4],
        [2, 3, 5, 4],
        [1, 1, 4, 5],
        [2, 3, 5, 4]]
#calculating mean and standard deviation
mean=np.mean(data,axis=0)
std=np.std(data,axis=0)

#draw figure
fig = go.Figure()
c = random.choice(hex_colors_only)
fig.add_trace(go.Scatter(x=np.arange(4), y=mean+std,
                                     mode='lines',
                                     line=dict(color=c,width =0.1),
                                     name='upper bound'))
fig.add_trace(go.Scatter(x=np.arange(4), y=mean,
                         mode='lines',
                         line=dict(color=c),
                         fill='tonexty',
                         name='mean'))
fig.add_trace(go.Scatter(x=np.arange(4), y=mean-std,
                         mode='lines',
                         line=dict(color=c, width =0.1),
                         fill='tonexty',
                         name='lower bound'))
fig.show()