Convert header into row

后端 未结 2 766
青春惊慌失措
青春惊慌失措 2020-12-19 15:00

I have a table like this.

user    01/12/15    02/12/15 someBool
u1      100         300      true
u2      200        -100      false
u3     -50          200          


        
2条回答
  •  醉话见心
    2020-12-19 15:29

    You need melt:

    df = pd.melt(df, id_vars=['user','someBool'], var_name='date')
    print (df)
      user someBool      date  value
    0   u1     True  01/12/15    100
    1   u2    False  01/12/15    200
    2   u3     True  01/12/15    -50
    3   u1     True  02/12/15    300
    4   u2    False  02/12/15   -100
    5   u3     True  02/12/15    200
    

    Another solution with stack:

    df = df.set_index(['user','someBool'])
           .stack()
           .reset_index(name='value')
           .rename(columns={'level_2':'date'})
    print (df)
      user someBool      date  value
    0   u1     True  01/12/15    100
    1   u1     True  02/12/15    300
    2   u2    False  01/12/15    200
    3   u2    False  02/12/15   -100
    4   u3     True  01/12/15    -50
    5   u3     True  02/12/15    200
    

提交回复
热议问题