How to get the caller script name

Question

I\'m using Python 2.7.6 and I have two scripts:

outer.py

import sys
import os

print \"Outer file launching...\"
os.system(\'inner.py\')

Answer 1

On linux you can get the process id and then the caller name like so.

p1.py

import os
os.system('python p2.py')

p2.py

import os

pid = os.getppid()
cmd = open('/proc/%d/cmdline' % (pid,)).read()
caller = ' '.join(cmd.split(' ')[1:])
print caller

running python p1.py will yield p1.py I imagine you can do similar things in other OS as well.