c# generic with slight difference for types?

Question

Notice the two extensions, one for float, one for Vector3.

Notice there\'s only a slight difference in the var( call.

In c# could these be writt

Answer 1

You can define your method as follows:

public static IEnumerator Tweeng(this float duration,
         System.Action var, T aa, T zz, Func thing)
{
    float sT = Time.time;
    float eT = sT + duration;

    while (Time.time < eT)
    {
        float t = (Time.time - sT) / duration;
        var(thing(aa, zz, t));
        yield return null;
    }

    var(zz);
}

And then using it:

float a = 5;
float b = 0;
float c = 0;
a.Tweeng(q => {}, b, c, Mathf.SmoothStep);

Or:

float a = 0;
Vector3 b = null;
Vector3 c = null;
a.Tweeng(q => {}, b, c, Vector3.Lerp);

Alternatively, if you want to get rid of the method passing, you can have simple overloads to handle it:

public static IEnumerator Tweeng(this float duration, System.Action var, float aa, float zz)
{
    return Tweeng(duration, var, aa, zz, Mathf.SmoothStep);
}
public static IEnumerator Tweeng(this float duration, System.Action var, Vector3 aa, Vector3 zz)
{
    return Tweeng(duration, var, aa, zz, Vector3.Lerp);
}

private static IEnumerator Tweeng(this float duration,
         System.Action var, T aa, T zz, Func thing)
{
    float sT = Time.time;
    float eT = sT + duration;

    while (Time.time < eT)
    {
        float t = (Time.time - sT) / duration;
        var(thing(aa, zz, t));
        yield return null;
    }

    var(zz);
}

And then using it:

float a = 5;
float b = 0;
float c = 0;
a.Tweeng(q => {}, b, c);

Or:

float a = 0;
Vector3 b = null;
Vector3 c = null;
a.Tweeng(q => {}, b, c);

---

Stub methods to compile in LINQPad/without unity:

public class Mathf { public static float SmoothStep(float aa, float zz, float t) => 0; }
public class Time { public static float time => DateTime.Now.Ticks; }
public class Vector3 { public static Vector3 Lerp(Vector3 aa, Vector3 zz, float t) => null; }