I have a more basic Run Length Encoding question compared to many of the questions about this topic that have already been answered. Essentially, I\'m trying to take the str
You can use itertools.groupby():
from itertools import groupby
grouped = [list(g) for k, g in groupby(string)]
This will produce your per-letter groups as a list of lists.
You can turn that into a RLE in one step:
rle = ''.join(['{}{}'.format(k, sum(1 for _ in g)) for k, g in groupby(string)])
Each k is the letter being grouped, each g an iterator producing N times the same letter; the sum(1 for _ in g) expression counts those in the most efficient way possible.
Demo:
>>> from itertools import groupby
>>> string = 'aabccccaaa'
>>> [list(g) for k, g in groupby(string)]
[['a', 'a'], ['b'], ['c', 'c', 'c', 'c'], ['a', 'a', 'a']]
>>> ''.join(['{}{}'.format(k, sum(1 for _ in g)) for k, g in groupby(string)])
'a2b1c4a3'