What is an idiomatic way to collect an iterator of &T into a collection of Ts?

Question

I need to collect an iterator over a slice of &strs into a collection of &strs. The problem is that the iterator yields &&str

Answer 1

If T implements Copy then you can use Iterator::copied. Otherwise, if it implements Clone then you can use Iterator::cloned. Like any immutable reference, &str implements both Clone and Copy, so you can use copied:

let hashset: HashSet<&str> = words.iter().copied().collect();