Can't form Range with end < start Check range before doing for loop?

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孤城傲影
孤城傲影 2020-12-19 11:07

I\'m encountering a change in the swift code which i do not quite understand.

var arr = []
for var i = 1; i <= arr.count; i += 1
{
    print(\"i want to          


        
3条回答
  •  Happy的楠姐
    2020-12-19 11:15

    If you just want to iterate over a collection, then use the for in syntax.

    for element in arr {
        // do something with element
    }
    

    If you also need access to the index of the element at each iteration, you can use enumerate(). Because indices are zero based, the index will have the range 0...

    for (index, element) in arr.enumerate() {
    
        // do something with index & element
    
        // if you need the position of the element (1st, 2nd 3rd etc), then do index+1
        let position = index+1
    }
    

    You can always add one to the index at each iteration in order to access the position (to get a range of 1..).

    If none of these solve your problem, then you can use the range 0.. to iterate over the indices of your array, or as @vacawama says, you could use the range 1.. to iterate over the positions.

    for index in 0..

    for position in 1..

    0..<0 cannot crash for an empty array as 0..<0 is just an empty range, and 1.. cannot crash for an empty array as 1..<1 is also an empty range.

    Also see @vacawama's comment below about using stride for safely doing more custom ranges. For example (Swift 2 syntax):

    let startIndex = 4
    for i in startIndex.stride(to: arr.count, by: 1) {
        // i = 4, 5, 6, 7 .. arr.count-1
    }
    

    Swift 3 syntax:

    for i in stride(from: 4, to: arr.count, by: 1) {
        // i = 4, 5, 6, 7 .. arr.count-1
    }
    

    This is where startIndex is the number to start the range at, arr.count is the number that the range will stay below, and 1 is the stride length. If your array has less elements than the given starting index, then the loop will never be entered.

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