Counting unique words in python

Question

In direct, my code so far is this :

from glob import glob
pattern = \"D:\\\\report\\\\shakeall\\\\*.txt\"
filelist = glob(pattern)
def countwords(fp):
    w         


        

Answer 1

If you want to get count of each unique word, then use dicts:

words = ['Hello', 'world', 'world']
count = {}
for word in words :
   if word in count :
      count[word] += 1
   else:
      count[word] = 1

And you will get dict

{'Hello': 1, 'world': 2}