Nested templates vs shift operator

Question

I have been reading all around about be aware >> as ending of nested template and >> as shift operator...

Now I have tried it i

Answer 1

This code works exactly what I want (map of pairs) but I supposed to get some error about >>

C++0x has fixed this. So if you're not getting any error with MSVS2010, then its no wonder, as MSVS2010 has implemented some of C++0x features.

Also, even with C++03, many compilers handle such cases, though not required by the Standard(2003).