How to sort an array in a single loop?

Question

So I was going through different sorting algorithms. But almost all the sorting algorithms require 2 loops to sort the array. The time complexity of Bubble sort & Insert

Answer 1

Here, a single-loop Bubble Sort in Python:

def bubbly_sortish(data):
    for _ in xrange(len(data)**2):
        i, j = _/len(data), _%len(data)
        if i data[j]:
            data[i], data[j] = data[j], data[i]

A = [5, 1, 2, 3, 5, 6, 10]
bubbly_sortish(A)

print A            

Of course this is a joke. But this shows the number of loops has little to do with algorithm complexity.

Now, if you're asking if it is possible to sort an array with O(n) comparisons, no, it's not possible. The lower bound is Ω(n log n) for comparison-based sorting algorithms.