Array division- translating from MATLAB to Python

Question

I have this line of code in MATLAB, written by someone else:

c=a.\'/b

I need to translate it into Python. a, b, and c are all arrays. The d

Answer 1

In Matlab, A.' means transposing the A matrix. So mathematically, what is achieved in the code is A^T/B.

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How to go about implementing matrix division in Python (or any language) (Note: Let's go over a simple division of the form A/B; for your example you would need to do A^T first and then A^T/B next, and it's pretty easy to do the transpose operation in Python |left-as-an-exercise :)|)

You have a matrix equation C*B=A (You want to find C as A/B)

RIGHT DIVISION (/) is as follows:

C*(B*B^T)=A*B^T

You then isolate C by inverting (B*B^T)

i.e.,

C = A*B^T*(B*B^T)' ----- [1]

Therefore, to implement matrix division in Python (or any language), get the following three methods.

• Matrix multiplication
• Matrix transpose
• Matrix inverse

Then apply them iteratively to achieve division as in [1].

Only, you need to do A^T/B, therefore your final operation after implementing the three basic methods should be:

A^T*B^T*(B*B^T)'

Note: Don't forget the basic rules of operator precedence :)