Assigning value to function returning reference

Question

#include
using namespace std;

int &fun()
{
  static int x = 10;
  return x;
}
int main()
{
   fun() = 30;
   cout << fun();
   return 0;
}         


        

Answer 1

L-value is a locator-value. It means it has address. A reference clearly has an address. The lvalue required you can get if you return from fun() by value:

#include
using namespace std;

int fun()
{
  static int x = 10;
  return x;
}
int main()
{
   fun() = 30;
   cout << fun();
   return 0;
}