passing argument makes pointer from integer

Question

I can\'t find my problem. keeps giving me these errors:

\"c:2:5: note: expected \'int *\' but argument is of type \'int\'\"
\"c:28:1: warning: passing argume         


        

Answer 1

Try this.

#include 
#include 

int CountEvenNumbers(int numbers[], int length);
int main(void)
{
    int length;
    int X;int Z; int Y; int W;
    X=0;Y=0;Z=0;W=0;
    printf("Enter list length\n");
    scanf("%d",&length);

    int *numbers = (int*) calloc(length, sizeof(int)); //***************


    if (length<=0)
    {printf("sorry too low of a value\n");
    return 0;}
    else
    {
        printf("Now, enter %d integers\n",length);
        for (X=0;X